3n^2-63n-240=0

Solution for 3n^2-63n-240=0 equation:

3n^2-63n-240=0

a = 3; b = -63; c = -240;
Δ = b2-4ac
Δ = -632-4·3·(-240)
Δ = 6849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6849}=\sqrt{9*761}=\sqrt{9}*\sqrt{761}=3\sqrt{761}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-3\sqrt{761}}{2*3}=\frac{63-3\sqrt{761}}{6}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+3\sqrt{761}}{2*3}=\frac{63+3\sqrt{761}}{6}
$